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29-10-2020
Engineering

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At 7:00PM the temperature was 40 degrees F. If the temperature dropped steadily at a rate of 6 degrees per hour, what was the temperature at 11:00 PM? Do you know what it is

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31-10-2020

Answer:

Temperature at 11:00 PM = 16 degree

Explanation:

Given:

Temperature at 7:00 PM = 40 degree

Decrease rate = 6 degree per hour

Find:

Temperature at 11:00 PM

Computation:

Total time = 11 - 7 = 4 hour

Total decrease in temperature = 4 x 6 = 24 degree

Temperature at 11:00 PM = 40 - 24

Temperature at 11:00 PM = 16 degree

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