Respuesta :
Answer:
P[2qp] = 0,467 or 46,7 %
Step-by-step explanation:
The probability of two of seven chemistry professors is equal to:
P[2 qp] = quantity of combinations of seven elements taken in groups of two, over total quantity of events, therefore
The total quantity of combinations is:
3 statistics professors + 7 chemistry professors taken in groups of 2 that is:
Te = (3 + 7) ! / 2!*(10-2)!
Te = 9!/ 2!*5! ⇒ Te = 9*8*7*6*5!/2!*8! ⇒ Te = 9*8!/2*8!
Te = 45
And successful events are:
C₇,₂ = 7!/2!*(7-2)!
C₇,₂ = 21
Finally, the probability that both professors are chemistry professors is:
P[2qp] = 21/45
P[2qp] = 0,467 or 46,7 %
The probability of selecting both professors are chemistry professors will be 0.4667 or 46.67%.
What is probability?
Probability means possibility. It deals with the occurrence of a random event. The value of probability can only be from 0 to 1. Its basic meaning is something is likely to happen. It is the ratio of the favorable event to the total number of events.
Three statistics professors and seven chemistry professors are available to be advisors to a student organization.
The student organization needs two of the professors to be advisors.
If each professor has an equal chance of being selected.
The probability that both professors are chemistry professors will be
The total quantity of combinations will be
[tex]\rm T = \ ^{10} C _ 2 = 45[/tex]
And successfull events will be
[tex]\rm F = \ ^7C_2 = 21[/tex]
Then the probability will be
[tex]\rm P = \dfrac{F}{T}\\\\\\P = \dfrac{21}{45}\\\\\\P = 0.4667 \ or \ 46.67 \%[/tex]
More about the probability link is given below.
https://brainly.com/question/795909
