Customers arrive to a bank according to a Poisson process having a rate of 8.6 customers per hour. Suppose we begin observing the bank at some point in time. (a) What is the probability that 3 customers arrive in the first 30 minutes

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Answer:

The value is [tex]P(X = 3) = 0.1798[/tex]

Step-by-step explanation:

From the question we are told  that

    The rate is  [tex]\lambda = 8.6 \ hr ^{-1}[/tex]

General probability distribution for Poisson distribution is mathematically represented

                [tex]P(X = x) = \frac{(\lambda * t)^{x} }{x!} * e^{-\lambda * t}[/tex]

Given that is in per hour then the unit of t is in hours

Generally  30 minutes   = [tex]0.5 \ hours[/tex]

Generally the probability that 3 customers arrive in the first 30 minutes is mathematically represented

        [tex]P(X = 3) = \frac{( 8.6 * 0.5 )^{3} }{3!} * e^{-8.6 * 0.5 }[/tex]

=>      [tex]P(X = 3) = 0.1798[/tex]