Answer: The freezing point of the solution will be [tex]4.3^0C[/tex]
Explanation:
Depression in freezing point is given by:
[tex]\Delta T_f=i\times K_f\times m[/tex]
[tex]\Delta T_f=T_f^0-T_f=(5.5-T_f)^0C[/tex] = Depression in freezing point
i= vant hoff factor = 1 (for non electrolyte)
[tex]K_f[/tex] = freezing point constant = [tex]4.90^0C/m[/tex]
m= molality
[tex]\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}[/tex]
Weight of solvent (benzene)= 800 g = 0.8 kg
Molar mass of solute ( methyl salicylate) = 152.1 g/mol
Mass of solute ( methyl salicylate) = 30 g
[tex](5.5-T_f)^0=1\times 4.90^0C/m\times \frac{30g}{152.1 g/mol\times 0.8kg}[/tex]
[tex](5.5-T_f)0C=1.2[/tex]
[tex]T_f=4.3^0[/tex]
The freezing point of the solution will be [tex]4.3^0C[/tex]
