Answer:
B, C, B, A, B
Step-by-step explanation:
Recall soh cah toa
sin - > soh sin(ANGLE) = opposite/hypotenuse
cos -> cah cos(ANGLE) = adjacent/hypotenuse
tan -> toa tan(ANGLE) = opposite/adjacent
(letters correspond)
7) They ask for sinX, meaning we need to apply soh
sinX = opposite/hypotenuse
sinX = 30/34 = 15/17
B
8)
tan(ANGLE) = opposite/adjacent
tanZ = 12/35
C
9)
cos(ANGLE) = adjacent/hypotenuse
cosZ = 36/45 = 4/5
B
10 + 11 are attached. Hopefully, you understand. Have a nice day :)
