Answer:
Step-by-step explanation:
From the figure attached,
Point X is the midpoint of line AC.
Since coordinates of the midpoint of the segment joining endpoints [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by,
[tex](\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex]
Therefore, coordinates of the point X will be,
= [tex](\frac{0+2a}{2},\frac{2a+0}{2})[/tex]
= (a, a)
From triangle AXB,
Length of AB = 2a
Length of AX = [tex]\sqrt{(a-0)^2+(a-2a)^2}[/tex]
= [tex]a\sqrt{2}[/tex]
Length of BX = [tex]\sqrt{(a-0)^2+(a-0)^2}[/tex]
= [tex]a\sqrt{2}[/tex]
Length of AX = BX = [tex]a\sqrt{2}[/tex]
Therefore, triangle AXB is an isosceles triangle.
