Using the Fundamental Counting Theorem, it is found that 350 meals are possible.
It is a theorem that states that if there are n things, each with [tex]n_1, n_2, \cdots, n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:
[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]
Considering the menu described in the problem, we have that:
[tex]n_1 = 5, n_2 = 10, n_3 = 7[/tex].
Hence the number of meals possible is given by:
N = 5 x 10 x 7 = 350.
More can be learned about the Fundamental Counting Theorem at https://brainly.com/question/24314866
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