Peter sells 5 flavors of Gelato at his stand. Today he is selling Hazelnut, Chocolate, Tiramisu, Pistachio, and Strawberry. Allen wants to try three different scoops in his cone. Below is a list of possible combinations. What's missing?

The missing combinations are H-T-P and C-T-S.
The probability of an event is defined as the possibility of an event occurring against sample space.
[tex]\large { \boxed {P(A) = \frac{\text{Number of Favorable Outcomes to A}}{\text {Total Number of Outcomes}} } }[/tex]
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Permutation is the number of ways to arrange objects.
[tex]\large {\boxed {^nP_r = \frac{n!}{(n - r)!} } }[/tex]
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Combination is the number of ways to select objects.
[tex]\large {\boxed {^nC_r = \frac{n!}{r! (n - r)!} } }[/tex]
Let us tackle the problem!
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This problem is about Combination.
Peter is selling Hazelnut (H), Chocolate (C), Tiramisu (T), Pistachio (P), and Strawberry (S). Total Combinations will be:
[tex]^5 C_3 = \frac{5!}{( 5 - 3 )! 3!}[/tex]
[tex]^5 C_3 = \frac{5!}{ 2 ! 3 !}[/tex]
[tex]^5 C_3 = 5 \times 4 \div 2[/tex]
[tex]^5 C_3 = \boxed{10}[/tex]
List of Possible Combinations:
H-C-T
H-C-P
H-C-S
H-T-P
H-T-S
H-P-S
C-T-P
C-T-S
C-P-S
T-P-S
The missing combinations are H-T-P and C-T-S.
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Grade: High School
Subject: Mathematics
Chapter: Probability
Keywords: Probability , Sample , Space , Six , Dice , Die , Binomial , Distribution , Mean , Variance , Standard Deviation
Answer:
C-T-S
H-T-P
Step-by-step explanation:
Here, you want to combine 5 differents flavors selecting 3 of them. C(5, 3) = 10, so, there are 10 different arrangements, 8 of them were already selected, C-T-S and H-T-P are missing . Notice that S-T-H is not correct because H-T-S is already chosen and P-T-S is not correct because T-P-S is already chosen.