Answer:
[tex]M_2=2.75x10^{-3}M[/tex]
Explanation:
Hello.
In this case, since a dilution process is a process by which the concentration of a solution decreases due to the increase of volume by usually adding water, it is important to take into account that the moles remain unchanged:
[tex]n_1=n_2[/tex]
Whereas in terms of molarity (M=n/V) can be written as:
[tex]M_1V_1=M_2V_2[/tex]
In such a way, since the initial concentration is 4.68e-3 M and the volume of such solution is 250. mL, the final volume results from mixing 250 mL of this solution with 175 mL, that is, to a volume of 425 mL. Thus, the concentration turns out:
[tex]M_2=\frac{M_1V_1}{V_2} =\frac{4.68x10^{-3}M*250.mL}{425.mL} \\\\M_2=2.75x10^{-3}M[/tex]
Best regards.
If you dilute the cough syrup by adding 175 mL of water to a 250 mL sample of the cough syrup, the final concentration would be 0.00275 M
Using a simple dilution equation:
number of moles before dilution = number of moles after dilution
Recall that: number of moles = molarity x volume (MV)
Thus:
M1V1 = M2V2
In this case, M1 = 4.68 x 10-3 M, M2 = ? V1 = 250 mL, and V2 = 425 mL
M2 = 4.68 x 10^-3 x 250/425
= 0.00275 M
= 0.00275 M
More on dilution principle can be found here: https://brainly.com/question/13844449
