Shares in stock of a new company are selling for $3.75 per share. An investor has $800. Which inequality can be solved to show the number of shares s he can buy?

Respuesta :

Given:

Price of each share = $3.75

Total amount invertor has = $800

To find:

The inequality that can be solved to show the number of shares s he can buy.

Solution:

Let x be the number of shares he can buy.

Price of 1 share = $3.75

Price of x shares = $3.75x

An investor has $800.

The price of x shares must be less than or equal to the amount he has. So,

[tex]3.75x\leq 800[/tex]

Divide both sides by 3.75.

[tex]x\leq \dfrac{800}{3.75}[/tex]

[tex]x\leq 213.33...[/tex]

So, the maximum possible integer value of x is 213.

Therefore, the equation inequality is [tex]3.75x\leq 800[/tex] and he can buy 213 shares.