Answer:
The stopping distance for the car when the driver slams on her brakes is 7.38 m.
Explanation:
The distance traveled for the car after stopping can be found using the following equation:
[tex] v_{f}^{2} = v_{0}^{2} + 2ad [/tex]
Where:
vf is the final speed = 0 (it stops)
v₀ is the initial speed = 11 m/s
a is the acceleration = -8.2 m/s²
d is the distance =?
When the driver slams on her brakes the distance traveled is:
[tex]d = -\frac{v_{0}^{2}}{2a} = -\frac{(11 m/s)^{2}}{2*(-8.2 m/s^{2})} = 7.38 m[/tex]
Therefore, the stopping distance for the car when the driver slams on her brakes is 7.38 m.
I hope it helps you!
