The missing part of the question is :
given dm-2 cm and de 25 cm
Answer:
The correct answer is = 2500 N
Explanation:
Given:
External force (fe) = 200 N
dm- 2 cm = 0.02 m
de = 25 cm = 0.25 m
Balancing torque about elbow
Fm*dm = Fe*de
By putting value
fm*0.02 = 200*0.25
fm= 200*0.25/0.02
fm = 50/0.02
fm = 2500 N
Thus, the correct answer is = 2500 N
