We know, Current is given by :
[tex]I = \dfrac{EA}{\rho}[/tex]
Here, [tex]\rho[/tex] is resistivity and for iron.
[tex]\rho=9.71\times 10^{-8}\ \Omega\ m[/tex]
Putting [tex]\rho[/tex] in above equation, we get :
[tex]I = \dfrac{0.062\times \pi\times (2.3\times 10^{-3})^2}{4\times 9.71\times 10^{-8}}[/tex]
[tex]I=2.65\ A[/tex]
Therefore, the electron current is 2.65 A.
Hence, this is the required solution.
