Answer:
Step-by-step explanation:
in this problem, we are expected to use commination to arrive at a solution
Given data
number of employee= 25
number of team=3
The expression for combination is given as
C(n,r)=(nr)=n!/(r!(n−r)!)
C(25,3)=25!/(3!(25−3)!)
C(25,3)=25!/(3!(22!)
C(25,3)=25*24*23*22!/3!(22!)
C(25,3)=25*24*23*/3!
C(25,3)=25*24*23*/3*2*1
C(25,3)=25*24*23*/6
C(25,3)=13800/6
C(25,3)=2300 ways
The number of ways where a store manager arranges a group is 50,600.
Given that,
Based on the above information, the calculation is as follows:
[tex]= ^25C_4 \times 4C_1\\\\= \frac{25!}{4!(25-4)!} \times \frac{4!}{1!(4-1)!} \\\\= \frac{25!}{4! \times 21!} \times \frac{4!}{1! \times 3!} \\\\= 12,650 \times 4[/tex]
= 50,600
Therefore we can conclude that the number of ways where a store manager arranges a group is 50,600.
Learn more: brainly.com/question/16115373
