Answer:
[tex]\epsilon=1.2\times 10^{-3}\ V[/tex]
Explanation:
Given that,
Length of a wire, l = 1.95 m
Speed of the wire, v = 15.5 m/s
The vertical component of Earth's magnetic field in this region is 40.0 μT directed downward.
We need to find the induced emf between the ends of the wire and determine which end is positive. The induced emf for a wire is given by :
[tex]\epsilon=Blv\\\\\epsilon = 40\times 10^{-6}\times 1.95\times 15.5\\\\\epsilon=1.2\times 10^{-3}\ V[/tex]
So, the induced emf between the ends of the wire is [tex]1.2\times 10^{-3}\ V[/tex].
