Answer:
Explanation:
Process is isentropic that means the process is adiabatic .
[tex]PV^\gamma = constant \\P^{(1 -\gamma)}\times T^\gamma = constant[/tex]
[tex]\frac{T_1}{T_2} = \frac{ P_1 ^ {(\gamma-1) }}{P_2^{(\gamma-1 )}}[/tex]
For air
[tex]\gamma = 1.4[/tex]
[tex]\frac{293}{T_2} = \frac{ 483^ {(1.4-1) }}{79^{(1.4-1 )}}[/tex]
[tex]\frac{293}{T_2} = 2.06[/tex]
[tex]T_2 = 142 K[/tex]
= - 131 ⁰C .
