Answer:
Empirical formula: C3H30
Molecular formula: C6H6O2
Explanation:
The empirical formula can be calculated thus:
65.45% C - 65.45g
5.45% H - 5.45g
29.09% O - 29.09g
We convert each mass to mole by dividing by their respective atomic mass:
C = 65.45/12 = 5.45mol
H = 5.45/1 = 5.45mol
O =29.09/16 = 1.82mol
Next, we divide each mole value by the smallest value;
C = 5.45mol/1.82 = 2.99
H = 5.45mol/1.82 = 2.99
O = 1.82mol/1.82 = 1
Approximately, the empirical ratio of C, H and O is 3:3:1 i.e. C3H3O
Molecular formula is calculated thus:
(C3H3O)n = 100g/mol
{12(3) + 1(3) + 16}n = 100
(36+3+16)n = 100
(55)n = 100
n = 100/55
n = 1.82
n = 2
Molecular formula= (C3H3O)2
C6H6O2
