Answer: 0.1271
Step-by-step explanation:
Let p= probability of the students in a university are baseball players.
Given: p= 0.40 , sample size : n= 781
The probability that the sample proportion of baseball players will be greater than 43% will be:
[tex]P(p>0.43)=P(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}>\dfrac{0.43-0.41}{\sqrt{\dfrac{0.41(1-0.41)}{781}}}\\\\=P(Z>1.14)\ \ \ [Z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}]\\\\=1-P(Z<1.14)\\\\=1- 0.8729=0.1271[/tex]
Hence, the probability that the sample proportion of baseball players will be greater than 43% = 0.1271
