By using Newton's second law, the cart's acceleration is 4.2 m/[tex]s^{2}[/tex]
Given that a spring scale is used to exert a net force of 2.7 N on a cart.
If the cart's mass is 0.64 kg, then, we can use Newton's second law to solve the question.
F = ma
Force F = 2.7 N
Mass m = 0.64 kg
Acceleration a = ?
Substitute all the parameters into the formula
2.7 = 0.64a
a = 2.7/0.64
a = 4.2 m/[tex]s^{2}[/tex]
Therefore, the cart's acceleration is 4.2 m/[tex]s^{2}[/tex]
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