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Tangela earns the same amount each week by babysitting. When she started this job, she had $200 in her savings account. The table shows Tangela's savings account balance for her first month of work. Week 0 1 2 3 4 Balance $200 $350 $500 $650 $800 Let x represent the number of weeks Tangela has been working and let y represent Tangela's account balance. Which equation, expressed in Slope-Intercept form, represents the amount of money in Tangela's bank account over time?

y=150x+200

y=200x−150

y=150x−200

y=200x+150

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Answer:

y=150x+200

Step-by-step explanation:

Given that:

Week : ____ 0___ 1 ___ 2 ____3 _____4

Balance : __200_350 _ 500 _ 650 ___800

Amount had in savings account = $200 before starting the job

x = number of weeks spent working

y = account balance

Slope intercept formula :

y = mx + c

C = intercept ; value of y when x = 0 = 200

m = slope or gradient = change in salary per month (350 - 200 = 500 - 350 = 650 - 500 = 800 - 650 = 150

Hence,

y = 150x + 200

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