Respuesta :

Lampa20
numbers 27 and 81 have 27 as common factor which is equal to 3^3. Noting that we can put 27 before brackets write it in form 3^3 and that third root and cube will trim.

[tex] \sqrt[3]{27x - 81} - 5=[/tex]
[tex] \sqrt[3]{27(x-3)} - 5 =[/tex]
[tex] \sqrt[3]{3^3(x-3)} - 5= [/tex]
[tex]3 \sqrt[3]{x-3} - 5 [/tex]

-5 means that graph is shifted 5 to down.
-3 means it is shifted to right by -3
3 and ∛ represent scaling of graph which can be seen and tested once you draw it. It is harder to explain it with words.
MrRoyal

The equivalent expression of [tex]\sqrt[3]{27x - 81} - 5[/tex] is [tex]3 \sqrt[3]{(x - 3)} - 5[/tex]

The expression is given as:

[tex]\sqrt[3]{27x - 81} - 5[/tex]

Rewrite the expression, as an equation

[tex]y = \sqrt[3]{27x - 81} - 5[/tex]

Factor out 27, from the radical expression

[tex]y = \sqrt[3]{27(x - 3)} - 5[/tex]

Express 27 as the cube of 3

[tex]y = \sqrt[3]{3^3(x - 3)} - 5[/tex]

Rewrite the radical expression, as a product

[tex]y = \sqrt[3]{3^3 * (x - 3)} - 5[/tex]

Take the cube root of 3^3

[tex]y =3 \sqrt[3]{(x - 3)} - 5[/tex]

Rewrite as:

[tex]3 \sqrt[3]{(x - 3)} - 5[/tex]

Hence, the equivalent expression of [tex]\sqrt[3]{27x - 81} - 5[/tex] is [tex]3 \sqrt[3]{(x - 3)} - 5[/tex]

Read more about equivalent expressions at:

https://brainly.com/question/2972832

Otras preguntas