[tex]\tt Step-by-step~explanation:[/tex]
[tex]\tt Solve~for~y:[/tex]
To solve for y, we have to move all of the terms that do not equal to y on one side, and let y be on the other side alone. Do this by subtracting 3x on both sides to cancel it out from the left side and bring it to the right.
[tex]\tt 3x-3x+y=-5-3x\\y=-5-3x\\y=-3x-5[/tex]
[tex]\tt Solve~for~x:[/tex]
To solve for x, we will do the same thing we did to solve for y: move all the terms that do not equal to x to one side, and leave x on another side of the equation. We can do this by first subtracting y from both sides.
[tex]\tt3x+y-y=-5-y\\3x=-y-5[/tex]
Then, we divide all terms by 3 to isolate the x.
[tex]\tt \frac{3x}{3}=x\\\\ \frac{-y}{3}=\frac{-y}{3} \\\\\frac{-5}{3}=\frac{-5}{3}[/tex]
[tex]\tt x=-\frac{y}{3} -\frac{5}{3}[/tex]
[tex]\lare\boxed{\tt Our~final~answer:~y=-3x=5,~x=-\frac{y}{3}-\frac{5}{3} }[/tex]
