Answer:
2.91M is the concentration of the household ammonia solution
Explanation:
18.2mL of a 0.800M HCl solution to neutralize 5.00mL
The reaction of HCl with NH3 is:
HCl + NH3 → NH4Cl
Thus, the moles of HCl needed to neutralize the household are equal to moles of NH3. That is:
18.2mL = 0.0182L * (0.800mol / L) = 0.01456 moles HCl = Moles NH3.
In 5.00mL = 0.005L:
0.01456 moles NH3 / 0.005L =
2.91M is the concentration of the household ammonia solution
