Answer:
Work it like a normal algebra problem to get ln x on one side. Then use a calculator or log tables.
Explanation:
Until you get to the actual logarithm the math is the same as for any algebra equation.
2
−
6
×
ln
(
x
)
=
10
;
−
6
ln
(
x
)
=
8
;
ln
(
x
)
=
−
(
4
3
)
NOW we take the antilog, inverse, or exponential of both sides:
e
ln
(
x
)
=
e
−
(
4
3
)
;
x
=
0.264
CHECK:
2
−
6
×
ln
(
x
)
=
10
;
2
−
6
ln
(
0.264
)
=
10
2
−
6
(
−
1.33
)
=
10
;
2
−
(
−
8
)
=
10
;
10
=
10
CORRECT!
