Answer:
Step-by-step explanation:
49y^2 - 25x^2 - 196y - 200x = 1429
49y^2-196y+196 - 25x^2-200x-400 = 1429+196-400
49(y-2)^2 - 25(x+4)^2 = 1225
(y-2)^2/25 - (x-4)^2/49 = 1
So now you know that you have an hyperbola with
center at (-4,2)
foci at (-4,2±[tex]\sqrt{74}[/tex])
vertices at (-4,2±5)
asymptotes 7y±20 = ∓5x+14
