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Two long straight wires carry currents perpendicular to the xy plane. One carries a current of IA = 10 A and passes through the point x = 4 cm on the x axis. The second wire has a current of IB = 68 A and passes through the point y = 7 cm on the y axis. What is the magnitude of the resulting magnetic field at the origin? Write your answer in micro-tesla.

Respuesta :

batolisis

Answer:

20 * 10^-7 Tesla

Explanation:

Given Data:

Wire A passes through ( 4, 0 ) and has a current (i1) = 10 A

distance from origin ( r1 ) = 4

Wire B passes through ( 0 , 7 ) and has a current of 68A

distance from origin ( r2 ) = 7

The magnitude of the resulting magnetic field at the origin

Bnet = B1 + B2

Magnitude of Bnet = [tex]\sqrt{B_{1} ^{2} } + B^{2} _{2}[/tex]

Attached below is the detailed solution

Ver imagen batolisis