Answer:
Margin of Error = 11.16
Step-by-step explanation:
A random sample of 17 hotels in Orlando had an average nightly room rate of $165.40 with a sample standard deviation of $21.70. The margin of error for a 95% confidence interval around this sample mean is
The formula for Margin of Error =
z × Standard deviation/√n
z = z score of 95% confidence Interval = 1.96
Standard deviation = $21.70
Random sample = 17
1.96 × 21.70/√17
= 11.16
Margin of Error = 11.16
