Answer:
t = 1.5 s and s(t) = 36 feet
Step-by-step explanation:
The height reached by an object as a function of time t is given by :
[tex]s(t)= -16t^2+48t[/tex] ...(1)
t is in seconds
To find the maximum height, put [tex]\dfrac{dh}{dt}=0[/tex]
[tex]\dfrac{d( -16t^2+48t)}{dt}=0\\\\-32t+48=0\\\\t=\dfrac{48}{32}\\\\t=1.5\ s[/tex]
It will take 1.5 seconds to reach its maximum height.
Put t = 1.5 s in equation (1), such that,
[tex]s(1.5)= -16(1.5)^2+48(1.5)\\\\s(t)=36\ \text{feet}[/tex]
The maximum height reached by the object is 36 feet.
