this would be easer to factor
(x+3)(x+4)=0
x+3=0
x+4=0
x=-3 and -4
bu tif want quadratic
in form
ax^2+bx+c=0
x=[tex] \frac{-b+/- \sqrt{b^2-4ac} }{2a} [/tex]
ax^2+bx+c=0
1x^2+7x+12=0
a=1
b=7
c=12
x=[tex] \frac{-b+/- \sqrt{b^2-4ac} }{2a} [/tex]
x=[tex] \frac{-7+/- \sqrt{7^2-4(1)(12)} }{2(1)} [/tex]
x=[tex] \frac{-7+/- \sqrt{49-48} }{2} [/tex]
x=[tex] \frac{-7+/- \sqrt{1} }{2} [/tex]
x=[tex] \frac{-7+/- 1}{2} [/tex]
x=-6/2 or -8/2
x=-3 or -4
