If tan m = One-half and tan n = –6, what is the exact value of tan(m + n)?

Negative StartFraction 11 Over 2 EndFraction
Negative StartFraction 11 Over 8 EndFraction
StartFraction 11 Over 8 EndFraction
StartFraction 11 Over 4 EndFraction

If tan m Onehalf and tan n 6 what is the exact value of tanm n Negative StartFraction 11 Over 2 EndFraction Negative StartFraction 11 Over 8 EndFraction StartFr class=

Respuesta :

Answer:

B. -11/8

Step-by-step explanation:

Given:

tan m = ½

tan n = -6

Required:

Exact value of tan(m + n)

Solution:

Find m and n:

[tex] tan (m) = \frac{1}{2} [/tex]

[tex] tan (m) = 0.5 [/tex]

[tex] m = tan^{-1}(0.5) [/tex]

m = 26° (approximated)

[tex] tan (n) = -6 [/tex]

[tex] n = tan^{-1}(-6) [/tex]

n = -80° = 280° (i.e. 360 - 80)

Exact value of tan(m + n) = tan(26 + 280)

tan(306)

tan(307) = -1.37638192 ≈ -11/8

Answer:

B)  -11/8

Step-by-step explanation:

its correct on edge