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A set of three resistors are set up in parallel. The resistor values are R1 = 3.0 Ohms, R2 = 11.0 Ohms, and R3 = 7.5 Ohms.

What is the total resistance of this circuit?

Respuesta :

onyebuchinnaji

Answer:

The total resistance in the circuit is 1.79 ohms

Explanation:

Given;

first resistor, R1 = 3.0 ohms

second resistor, R2 = 11.0 ohms

third resistor, R3 = 7.5 ohms

The total resistance in the circuit is given by;

[tex]\frac{1}{C_T} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}\\\\\frac{1}{C_T} =\frac{R_2R_3 + R_1R_3+R_1R_2}{R_1R_2R_3} \\\\ C_T = \frac{R_1R_2R_3}{R_2R_3 + R_1R_3+R_1R_2}\\\\ C_T = \frac{(3*11*7.5)}{(11*7.5) + (3*7.5)+(3*11)}\\\\C_T = \frac{247.5}{138}\\\\C_T = 1.79 \ ohms[/tex]

Therefore, the total resistance in the circuit is 1.79 ohms

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