Respuesta :
x + 2 < 5 and x - 7 > -6
x < 5 - 2 and x > -6 + 7
x < 3 and x > 1
Therefore, solutin is {x | 1 < x < 3}
x < 5 - 2 and x > -6 + 7
x < 3 and x > 1
Therefore, solutin is {x | 1 < x < 3}