Respuesta :

caylus
Hello,

P(x)=x^3-5x^2+14x-5

P(-3)=(-3)^3-5*(-3)²+14*(-3)-5=-119
Remainder=-119

Answer:

The remainder is -119

Step-by-step explanation:

[tex](x^3 - 5x^2+ 14x - 5)[/tex] divide by (x+3)

we use the remainder theorem to find the remainder

We are given with x+3

[tex]x+3=0, x=-3[/tex]

To find remainder, we substitute -3 for x

[tex](x^3 - 5x^2+ 14x - 5)[/tex]

[tex]((-3)^3 - 5(-3)^2+ 14(-3) - 5)[/tex]

[tex]-27-45-42-5=-119[/tex]

The remainder is -119