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What is the molarity of a solution prepared from 34.5 grams of NaCl in 250.0 millilitres of solution?

Respuesta :

Answer:

2.36 mol/L

Explanation:

First, find mols of NaCl:

34.5 g NaCl x [tex]\frac{1 mol NaCl}{58.44g NaCl}[/tex] = 0.59 mol NaCl

molarity:

0.59 mol NaCl / 0.250 L = 2.36 mol/L

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