Answer:
[tex]-\frac{1}{15}<x<0[/tex]
Step-by-step explanation:
[tex]\frac{-1}{3x}> 5 \\\\\mathrm{Subtract\:}5\mathrm{\:from\:both\:sides}\\\\\frac{-1}{3x}-5>5-5\\\\Simplify\\-\frac{1}{3x}-5>0\\\\\mathrm{Simplify}\:-\frac{1}{3x}-5:\quad \frac{-1-15x}{3x}\\\\\frac{-1-15x}{3x}>0\\\\\mathrm{Multiply\:both\:sides\:by\:}3\\\frac{3\left(-1-15x\right)}{3x}>0\times\:3\\\\Simplify\\\\\frac{-1-15x}{x}>0\\\\\mathrm{Find\:the\:signs\:of\:the\:factors\:of\:}\frac{-1-15x}{x}\\\\\mathrm{Identify\:the\:intervals\:that\:satisfy\:the\:required\:condition:}\:>\:0\\\\[/tex]
[tex]-\frac{1}{15}<x<0[/tex]
