albracamonte05
contestada

As the result of experimental work, a student finds the density of a liquid to be 0.1369 g/mL. The known density of that liquid is 0.1478 g/mL. What is the percent error of this student's work [% error = (actual - experimental)/actual. Then multiply by 100]. Sig figs apply.

a 0.07374%
b 7.37%
c 7.375%
d 7.4%

Respuesta :

Stephen46

Answer:

The answer is option C

Explanation:

The percentage error of a certain measurement can be found by using the formula

[tex]P(\%) = \frac{error}{actual \: \: number} \times 100\% \\ [/tex]

From the question

actual density = 0.1478 g/mL

error = 0.1478 - 0.1369 = 0.0109

The percentage error is

[tex]P (\%) = \frac{0.0109}{0.1478} \times 100 \\ = 7.37483085...[/tex]

We have the final answer as

7.375 %

Hope this helps you

Otras preguntas