From the top of a 150 m high-rise building,

two cars on the same road below the

building are seen at an angle of depression

of 45° and 60° on each side of the tower.

Find the distance between the two cars,

correct to the nearest metre.

Respuesta :

Answer:

The distance between the two cars is approximately 237 meters.

Step-by-step explanation:

Let be P the top of the high-rise building and Q and R the location of the two cars from each side of the tower. Geometric figure is represented on image attached below. We calculate the distance between both cars ([tex]d[/tex]), measured in meters, by Trigonometric ratios:

[tex]d = QO + OR[/tex]

[tex]d = \frac{OP}{\tan 45^{\circ}} +\frac{OP}{\tan 60^{\circ}}[/tex]

Where [tex]OP[/tex] is the height of the building, measured in meters.

[tex]d = OP\cdot \left(\frac{1}{\tan 45^{\circ} }+\frac{1}{\tan 60^{\circ}} \right)[/tex]

If we know that [tex]OP = 150\,m[/tex], then:

[tex]d = (150\,m)\cdot \left(\frac{1}{\tan 45^{\circ}}+\frac{1}{\tan 60^{\circ}} \right)[/tex]

[tex]d \approx 236.603\,m[/tex]

The distance between the two cars is approximately 237 meters.

Ver imagen xero099