Answer: $34
Jenny=2 h (hammers) + 1 w (wrench)=$47
Penny=1 h + 3 w=$41
2h+1w=47
1h+3w=41
2h+1w=47
2h+6w=82
5w=35
w=7
h=20
1h+2w=1(20)+2(7)=$34
The cost of 1 hammer and 2 wrenches is $34
The two equations represent the information provided in the question:
2h + w = 47 equation 1
h + 3w = 41 equation 2
h represents the price of a hammer.
w represents the price of a wrench.
The above equations are simultaneous equations and would be solved using the elimination method.
To determine the price of a wrench, take the following steps:
Multiply equation 2 by 2
2h + 6w = 82 equation 3
Subtract equation 1 from 3
5w = 35
Divide both sides of the equation by 5
w = 7
To determine the price of a hammer, take the following steps:
Substitute for w in equation 1
2h + 7 = 47
2h = 47 - 7
2h = 40
h = 40/2
h = 20
The price of a hammer = $20
Price of two wrenches = $7 x 2 = 14
Total cost is 20 + 14 = $34
To learn more about simultaneous equations, please check: brainly.com/question/23589883?referrer=searchResults
