Given:
Larry pays $20.69 for 4 cases of soda 3 bags of chips.
One case of soda costs $1.55 more than one bag of chips.
To find:
The equation that represents this situation.
Solution:
Let cost of one bag of chips be $c. So,
Cost of One case of soda = $(c+1.55)
Cost of 4 cases of soda 3 bags of chips is
[tex]Cost=4(c+1.55)+3(c)[/tex]
It is given that Larry pays $20.69 for 4 cases of soda 3 bags of chips. So, the cost is $20.69 for 4 cases of soda 3 bags of chips.
[tex]4(c+1.55)+3c=20.69[/tex]
Therefore, the required equation is [tex]4(c+1.55)+3c=20.69[/tex].
