Can you break down how to solve the problem ?

Answer:
A. y = [tex]\frac{-5x}{2}[/tex] - 1
Step-by-step explanation:
Given parameters:
Equation of the line:
5x + 2y = 12
Coordinates = -2, 4
Unknown:
The equation of the line parallel to this line = ?
Every linear equation have the formula: y = mx + c
m is the slope of the line, c is the y- intercept
5x + 2y = 12
Express this equation as y = mx + c
2y = -5x + 12
y = [tex]\frac{-5}{2}x[/tex] + 6
The slope of this line is [tex]\frac{-5}{2}[/tex]
Slope of the line parallel is [tex]\frac{-5}{2}[/tex]
Coordinates = -2, 4, x = -2 and y = 4
m is [tex]\frac{-5}{2}[/tex]
Now let us solve for C, the y-intercept;
4 = - 2 x [tex]\frac{-5}{2}[/tex] + C
4 = 5 + C
C = -1
The equation of the line is therefore;
y = [tex]\frac{-5x}{2}[/tex] - 1