Answer:
m₁ = 75 kg
m₂ = 4 kg
r = 0.3 m
G = 6.67 x 10⁻¹¹ Nm²/kg²
F = 2.223 x 10⁻⁷ N
Explanation:
Given;
mass of the doctor, m₁ = 75 kg
mass of the baby, m₂ = 4 kg
length of the doctor's arm, r = 0.3 m
universal gravitation constant, G = 6.67 x 10⁻¹¹ Nm²/kg²
The gravitational force F, is calculated as;
[tex]F = \frac{Gm_1m_2}{r^2} \\\\F = \frac{(6.67*10^{-11})(75 \ kg) (4 \ kg)}{(0.3 \ m)^2} \\\\F = 2.223 *10^{-7} \ N[/tex]
