Given:
The sum of two consecutive odd integers is 2488.
To find:
The smallest of these integers
Solution:
Let the two consecutive odd integers are x and x+2.
Given that, sum of these two consecutive odd integers is 2488. So,
[tex]x+(x+2)=2488[/tex]
[tex]2x+2=2488[/tex]
Subtract 2 from both sides.
[tex]2x=2488-2[/tex]
[tex]2x=2486[/tex]
Divide both sides by 2.
[tex]x=\dfrac{2486}{2}[/tex]
[tex]x=1243[/tex]
So, the first odd integer is 1243 and second odd integer is 1243+2=1245.
Therefore, the smallest of these integers is 1243.
