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Suppose that we are doing batch testing with batches of size 12. Suppose that the probability that a batch of size 12 tests negative is .655. Determine the expected number (expected value) of tests needed for a group of size 12.

Respuesta :

MrRoyal

Answer:

[tex]E(x) = 7.86[/tex]

Step-by-step explanation:

Given

Represent the size with n and the probability with p

[tex]n = 12[/tex]

[tex]p = 0.655[/tex]

Required

Determine the expected value; E(x)

[tex]E(x) = np[/tex]

[tex]E(x) = 12 * 0.655[/tex]

[tex]E(x) = 7.86[/tex]

Hence, the expected value is 7.86

The expected value is 7.86.

Important information:

  • Group size = 12
  • Probability that a batch of size 12 tests negative is 0.655.

We need to find the expected number (expected value) of tests needed for a group of size 12.

Expected value:

The expected value is:

[tex]E(x)=np(x)[/tex]

Where, n is the batch size and p is the probability.

[tex]E(x)=12(0.655)[/tex]

[tex]E(x)=7.86[/tex]

Therefore, the expected value is 7.86.

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