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Lines b and a are intersected by line f. At the intersection of lines f and b, the bottom left angle is angle 4 and the bottom right angle is angle 3. At the intersection of lines f and a, the uppercase right angle is angle 1 and the bottom left angle is angle 2. Which set of equations is enough information to prove that lines a and b are parallel lines cut by transversal f? m∠4 = 110° and m∠3 = 70° m∠1 = 110° and m∠2 = 110° m∠1 = 110° and m∠3 = 70° m∠2 = 110° and m∠3 = 110°

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Answer:

m∠1 = 110° and m∠3 = 70°

Step-by-step explanation:

MrRoyal

The angles at the intersection of a transversal and parallel lines are supplementary angles.

The true statement is: [tex]\mathbf{\angle 1 = 110^o}[/tex] and [tex]\mathbf{\angle 3= 70}[/tex]

From the complete question, we  have:

  • [tex]\mathbf{\angle 1 = 110^o}[/tex]
  • Angle 1 is supplementary to angle 3

This means that:

[tex]\mathbf{\angle 1 + \angle 3= 180^o}[/tex]

Substitute [tex]\mathbf{\angle 1 = 110^o}[/tex]

[tex]\mathbf{110 + \angle 3= 180^o}[/tex]

Subtract 110 from both sides

[tex]\mathbf{\angle 3= 180 - 110}[/tex]

[tex]\mathbf{\angle 3= 70}[/tex]

Hence, the true statement is: [tex]\mathbf{\angle 1 = 110^o}[/tex] and [tex]\mathbf{\angle 3= 70}[/tex]

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