isaiahw0414
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A man and woman have a son who is color blind, a recessive sex-linked trait carried on the X chromosome, but neither parent is color blind. The woman is now pregnant with their second child. Which of the following statements is true about the second child? A daughter will be color blind because the father is a carrier of the recessive allele. A son will be color blind because the mother is a carrier of the recessive allele. A daughter will not be color blind because the father is not a carrier of the recessive allele. A son will be color blind because the father’s mother must have been a carrier for recessive allele.

Respuesta :

collinschiagozie03

Answer:

A daughter will not be color blind because the father is not a carrier of the recessive allele

adefioyelaoye

A man and woman have a son who is color blind, a recessive sex-linked trait

carried on the X chromosome, but neither parent is color blind therefore the

daughter will not be color blind because the father is not a carrier of the

recessive allele

Color blindness trait is sex-linked because the trait is carried on the

chromosomes. The female have XX chromosomes while the male have XY

chromosomes. The color blind trait in the son(XY) is as a result of the

woman donating the X chromosomes which is defective and the Y

chromosome came from the man which has no issues.

in this scenario, half of their male children will have normal vision while the

other half will be color blind. The father's X chromosome is normal and all the

girls(XX) will have normal vision but will have the color blind trait in their

chromosomes because the XX chromosome are donated from both the man

and woman.

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