We know, change in temperature is given by :
[tex]T_2-T_1=\dfrac{q}{mC_p(Gold)}[/tex]
Putting all given values, we get :
[tex]T_2-T_1=\dfrac{70\ cal}{20\ g\times 0.0310\ cal/g^o\ C}\\\\T_2-T_1=112.90^oC\\\\T_2-35^oC=112.90^oC\\\\T_2=(112.90+35)^oC\\\\T_2=147.9^oC[/tex]
Hence, this is the required solution.
