Answer:
4.34%
Explanation:
The accepted value for the density of rubber is 1.15 g/mL
Let the calculated value for the density of rubber is 1.2 g/mL
We need to find the percent error for rubber stopper. It can be calculated as follows :
[tex]\text{Error}=\dfrac{|\text{actual value-calculated value}|}{\text{actual value}}\times 100\\\\\text{Error}=\dfrac{1.15-1.2}{1.15}\times 100\\\\\text{Error}=4.34\%[/tex]
