Answer:
The distance covered by the projectile is 12.68 m
Explanation:
Given;
angle of projection, θ = 35.0°
speed of projectile, v = 11.5 m/s
The distance covered by the projectile is given by the range of the projection;
R = vt
[tex]R = \frac{v^2sin2\theta}{g} \\\\R = \frac{(11.5)^2 sin (2*35)}{9.8} \\\\R = 12.68 \ m[/tex]
Therefore, the distance covered by the projectile is 12.68 m.
