When a 40 resistor is connected across the
terminals of a 2 V battery, the number of
coulombs passing through the resistor per
second is:

Respuesta :

Answer:

Explanation:

resistance=40Ω

potential difference=2V

time=1s

no. of coulombs=?

V=IR

I=V/R=2/40=0.05A

I=Q/t

Q=It=[0.05][1]=0.05C