Answer:
Step-by-step explanation:
Hello, we can notice that f(-1)=0 so (x+1) is a factor and we can write.
[tex]f(x)=(x+1)(x^2-8x +12)\\\\=(x+1)(x-6)(x-2)[/tex]
The sum of the zeros is 8=6+2 and the product is 12=6*2
So the zeroes are 2, 6, -1
thanks
